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125213201341 = 650111926031
BaseRepresentation
bin111010010011101001…
…0011101001110111101
3102222012022201200022121
41310213102131032331
54022414034420331
6133304441242541
712021620436064
oct1644722351675
9388168650277
10125213201341
1149114651488
1220325793451
13ba66272ca7
1460bb8651db
1533cc9c2c11
hex1d2749d3bd

125213201341 has 4 divisors (see below), whose sum is σ = 125215192384. Its totient is φ = 125211210300.

The previous prime is 125213201303. The next prime is 125213201381. The reversal of 125213201341 is 143102312521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125213201341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125213201381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 898005 + ... + 1028026.

It is an arithmetic number, because the mean of its divisors is an integer number (31303798096).

Almost surely, 2125213201341 is an apocalyptic number.

It is an amenable number.

125213201341 is a deficient number, since it is larger than the sum of its proper divisors (1991043).

125213201341 is an equidigital number, since it uses as much as digits as its factorization.

125213201341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1991042.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 125213201341 its reverse (143102312521), we get a palindrome (268315513862).

The spelling of 125213201341 in words is "one hundred twenty-five billion, two hundred thirteen million, two hundred one thousand, three hundred forty-one".

Divisors: 1 65011 1926031 125213201341