Base | Representation |
---|---|
bin | 10111010100101111… |
… | …01011100111001001 |
3 | 1012022200101001221012 |
4 | 23222113223213021 |
5 | 201121113323311 |
6 | 5430314053305 |
7 | 622210223636 |
oct | 135227534711 |
9 | 35280331835 |
10 | 12522011081 |
11 | 5346392298 |
12 | 251571a235 |
13 | 1247355518 |
14 | 86b0a318d |
15 | 4d44d578b |
hex | 2ea5eb9c9 |
12522011081 has 2 divisors, whose sum is σ = 12522011082. Its totient is φ = 12522011080.
The previous prime is 12522011039. The next prime is 12522011137. The reversal of 12522011081 is 18011022521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12391251856 + 130759225 = 111316^2 + 11435^2 .
It is a cyclic number.
It is not a de Polignac number, because 12522011081 - 226 = 12454902217 is a prime.
It is a super-3 number, since 3×125220110813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (12522011581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6261005540 + 6261005541.
It is an arithmetic number, because the mean of its divisors is an integer number (6261005541).
Almost surely, 212522011081 is an apocalyptic number.
It is an amenable number.
12522011081 is a deficient number, since it is larger than the sum of its proper divisors (1).
12522011081 is an equidigital number, since it uses as much as digits as its factorization.
12522011081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 320, while the sum is 23.
The spelling of 12522011081 in words is "twelve billion, five hundred twenty-two million, eleven thousand, eighty-one".
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