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12523030352047 is a prime number
BaseRepresentation
bin1011011000111011111011…
…0001101001000010101111
31122100012010111221220210201
42312032332301221002233
53120134131232231142
642345000053414331
72431521236444365
oct266167661510257
948305114856721
1012523030352047
113a98a951826a6
1214a306963a3a7
136cabbbc95ab7
14314191751635
1516ab4585bab7
hexb63bec690af

12523030352047 has 2 divisors, whose sum is σ = 12523030352048. Its totient is φ = 12523030352046.

The previous prime is 12523030351933. The next prime is 12523030352057. The reversal of 12523030352047 is 74025303032521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12523030352047 - 243 = 3726937329839 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12523030351997 and 12523030352015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12523030352057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6261515176023 + 6261515176024.

It is an arithmetic number, because the mean of its divisors is an integer number (6261515176024).

Almost surely, 212523030352047 is an apocalyptic number.

12523030352047 is a deficient number, since it is larger than the sum of its proper divisors (1).

12523030352047 is an equidigital number, since it uses as much as digits as its factorization.

12523030352047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 37.

Adding to 12523030352047 its reverse (74025303032521), we get a palindrome (86548333384568).

The spelling of 12523030352047 in words is "twelve trillion, five hundred twenty-three billion, thirty million, three hundred fifty-two thousand, forty-seven".