Base | Representation |
---|---|
bin | 10111010100110111… |
… | …00110110110000010 |
3 | 1012022202022100112010 |
4 | 23222123212312002 |
5 | 201121344241010 |
6 | 5430352113350 |
7 | 622222041036 |
oct | 135233466602 |
9 | 35282270463 |
10 | 12523040130 |
11 | 5346a25447 |
12 | 2515b35856 |
13 | 1247625a23 |
14 | 86b2901c6 |
15 | 4d463a620 |
hex | 2ea6e6d82 |
12523040130 has 64 divisors (see below), whose sum is σ = 31108147200. Its totient is φ = 3222616320.
The previous prime is 12523040119. The next prime is 12523040141. The reversal of 12523040130 is 3104032521.
It is an interprime number because it is at equal distance from previous prime (12523040119) and next prime (12523040141).
It is a junction number, because it is equal to n+sod(n) for n = 12523040097 and 12523040106.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3008991 + ... + 3013149.
It is an arithmetic number, because the mean of its divisors is an integer number (486064800).
Almost surely, 212523040130 is an apocalyptic number.
12523040130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12523040130 is an abundant number, since it is smaller than the sum of its proper divisors (18585107070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12523040130 is a wasteful number, since it uses less digits than its factorization.
12523040130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7659.
The product of its (nonzero) digits is 720, while the sum is 21.
Adding to 12523040130 its reverse (3104032521), we get a palindrome (15627072651).
The spelling of 12523040130 in words is "twelve billion, five hundred twenty-three million, forty thousand, one hundred thirty".
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