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1252341431403 = 32927271426063
BaseRepresentation
bin10010001110010101010…
…111011011110001101011
311102201111211100022122220
4102032111113123301223
5131004243401301103
62355152343045123
7156323121346266
oct22162527336153
94381454308586
101252341431403
1144312a0a9217
121828667407a3
1391131477aaa
1444883bcdcdd
1522899dd7c53
hex123955dbc6b

1252341431403 has 8 divisors (see below), whose sum is σ = 1669795450368. Its totient is φ = 834890850024.

The previous prime is 1252341431399. The next prime is 1252341431441. The reversal of 1252341431403 is 3041341432521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1252341431403 - 22 = 1252341431399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1252341431443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 165150 + ... + 1591212.

It is an arithmetic number, because the mean of its divisors is an integer number (208724431296).

Almost surely, 21252341431403 is an apocalyptic number.

1252341431403 is a deficient number, since it is larger than the sum of its proper divisors (417454018965).

1252341431403 is a wasteful number, since it uses less digits than its factorization.

1252341431403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1718793.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 1252341431403 its reverse (3041341432521), we get a palindrome (4293682863924).

The spelling of 1252341431403 in words is "one trillion, two hundred fifty-two billion, three hundred forty-one million, four hundred thirty-one thousand, four hundred three".

Divisors: 1 3 292727 878181 1426063 4278189 417447143801 1252341431403