Base | Representation |
---|---|
bin | 10010001110010101100… |
… | …001010110011111111111 |
3 | 11102201112000020101221211 |
4 | 102032111201112133333 |
5 | 131004300032444411 |
6 | 2355152514505251 |
7 | 156323152425046 |
oct | 22162541263777 |
9 | 4381460211854 |
10 | 1252344031231 |
11 | 443130614537 |
12 | 182867595227 |
13 | 91131b78257 |
14 | 448842a955d |
15 | 2289a24d221 |
hex | 123958567ff |
1252344031231 has 32 divisors (see below), whose sum is σ = 1383236236800. Its totient is φ = 1129237200000.
The previous prime is 1252344031229. The next prime is 1252344031241. The reversal of 1252344031231 is 1321304432521.
It is a cyclic number.
It is not a de Polignac number, because 1252344031231 - 21 = 1252344031229 is a prime.
It is a super-2 number, since 2×12523440312312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1252344031193 and 1252344031202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1252344031241) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10841881 + ... + 10956781.
It is an arithmetic number, because the mean of its divisors is an integer number (43226132400).
Almost surely, 21252344031231 is an apocalyptic number.
1252344031231 is a deficient number, since it is larger than the sum of its proper divisors (130892205569).
1252344031231 is a wasteful number, since it uses less digits than its factorization.
1252344031231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115231.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1252344031231 its reverse (1321304432521), we get a palindrome (2573648463752).
The spelling of 1252344031231 in words is "one trillion, two hundred fifty-two billion, three hundred forty-four million, thirty-one thousand, two hundred thirty-one".
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