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12523470780047 is a prime number
BaseRepresentation
bin1011011000111101100100…
…0001101111011010001111
31122100020021012200222102212
42312033121001233122033
53120141032004430142
642345111505341035
72431535165146133
oct266173101573217
948306235628385
1012523470780047
113a991a0850787
1214a317103777b
136cac5c2c0996
143141d403b3c3
1516ab6e358d82
hexb63d906f68f

12523470780047 has 2 divisors, whose sum is σ = 12523470780048. Its totient is φ = 12523470780046.

The previous prime is 12523470780019. The next prime is 12523470780061. The reversal of 12523470780047 is 74008707432521.

It is a strong prime.

It is an emirp because it is prime and its reverse (74008707432521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12523470780047 - 26 = 12523470779983 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12523470779977 and 12523470780004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12523470180047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6261735390023 + 6261735390024.

It is an arithmetic number, because the mean of its divisors is an integer number (6261735390024).

Almost surely, 212523470780047 is an apocalyptic number.

12523470780047 is a deficient number, since it is larger than the sum of its proper divisors (1).

12523470780047 is an equidigital number, since it uses as much as digits as its factorization.

12523470780047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2634240, while the sum is 50.

The spelling of 12523470780047 in words is "twelve trillion, five hundred twenty-three billion, four hundred seventy million, seven hundred eighty thousand, forty-seven".