Base | Representation |
---|---|
bin | 1011011000111111111101… |
… | …1000101100010111000001 |
3 | 1122100021221001122202111001 |
4 | 2312033333120230113001 |
5 | 3120143341232043243 |
6 | 42345255415052001 |
7 | 2431560141223162 |
oct | 266177730542701 |
9 | 48307831582431 |
10 | 12524114331073 |
11 | 3a994a1045134 |
12 | 14a3310671001 |
13 | 6cb0327274c7 |
14 | 3142556bd769 |
15 | 16abaaacaa4d |
hex | b63ff62c5c1 |
12524114331073 has 2 divisors, whose sum is σ = 12524114331074. Its totient is φ = 12524114331072.
The previous prime is 12524114331041. The next prime is 12524114331083. The reversal of 12524114331073 is 37013341142521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12197779771024 + 326334560049 = 3492532^2 + 571257^2 .
It is a cyclic number.
It is not a de Polignac number, because 12524114331073 - 25 = 12524114331041 is a prime.
It is not a weakly prime, because it can be changed into another prime (12524114331083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6262057165536 + 6262057165537.
It is an arithmetic number, because the mean of its divisors is an integer number (6262057165537).
Almost surely, 212524114331073 is an apocalyptic number.
It is an amenable number.
12524114331073 is a deficient number, since it is larger than the sum of its proper divisors (1).
12524114331073 is an equidigital number, since it uses as much as digits as its factorization.
12524114331073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 37.
Adding to 12524114331073 its reverse (37013341142521), we get a palindrome (49537455473594).
The spelling of 12524114331073 in words is "twelve trillion, five hundred twenty-four billion, one hundred fourteen million, three hundred thirty-one thousand, seventy-three".
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