12524114331083 has 2 divisors, whose sum is σ = 12524114331084. Its totient is φ = 12524114331082.

The previous prime is 12524114331073. The next prime is 12524114331089. The reversal of 12524114331083 is 38013341142521.

It is a strong prime.

It is an emirp because it is prime and its reverse (38013341142521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12524114331083 - 2²⁰ = 12524113282507 is a prime.

It is a super-3 number, since 3×12524114331083³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12524114331089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6262057165541 + 6262057165542.

It is an arithmetic number, because the mean of its divisors is an integer number (6262057165542).

Almost surely, 2^{12524114331083} is an apocalyptic number.

12524114331083 is a deficient number, since it is larger than the sum of its proper divisors (1).

12524114331083 is an equidigital number, since it uses as much as digits as its factorization.

12524114331083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 38.

The spelling of 12524114331083 in words is "twelve trillion, five hundred twenty-four billion, one hundred fourteen million, three hundred thirty-one thousand, eighty-three".