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1252415324317 is a prime number
BaseRepresentation
bin10010001110011001110…
…001010100000010011101
311102201200222101110200111
4102032121301110002131
5131004421310334232
62355203542530021
7156325006415443
oct22163161240235
94381628343614
101252415324317
11443167889043
12182887436911
139114387a501
144488d946b93
15228a1632047
hex12399c5409d

1252415324317 has 2 divisors, whose sum is σ = 1252415324318. Its totient is φ = 1252415324316.

The previous prime is 1252415324297. The next prime is 1252415324351. The reversal of 1252415324317 is 7134235142521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1144170376281 + 108244948036 = 1069659^2 + 329006^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1252415324317 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1252415324317.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1252415394317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626207662158 + 626207662159.

It is an arithmetic number, because the mean of its divisors is an integer number (626207662159).

Almost surely, 21252415324317 is an apocalyptic number.

It is an amenable number.

1252415324317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252415324317 is an equidigital number, since it uses as much as digits as its factorization.

1252415324317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 201600, while the sum is 40.

The spelling of 1252415324317 in words is "one trillion, two hundred fifty-two billion, four hundred fifteen million, three hundred twenty-four thousand, three hundred seventeen".