Base | Representation |
---|---|
bin | 10010001110011010101… |
… | …010001110010101000111 |
3 | 11102201202000110102110121 |
4 | 102032122222032111013 |
5 | 131004434120240033 |
6 | 2355205234402411 |
7 | 156325250262532 |
oct | 22163252162507 |
9 | 4381660412417 |
10 | 1252430243143 |
11 | 443175248852 |
12 | 182890430407 |
13 | 911469a1c11 |
14 | 4489190ba19 |
15 | 228a2acc62d |
hex | 1239aa8e547 |
1252430243143 has 2 divisors, whose sum is σ = 1252430243144. Its totient is φ = 1252430243142.
The previous prime is 1252430243111. The next prime is 1252430243203. The reversal of 1252430243143 is 3413420342521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1252430243143 - 25 = 1252430243111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1252430243099 and 1252430243108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1252430943143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626215121571 + 626215121572.
It is an arithmetic number, because the mean of its divisors is an integer number (626215121572).
Almost surely, 21252430243143 is an apocalyptic number.
1252430243143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1252430243143 is an equidigital number, since it uses as much as digits as its factorization.
1252430243143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 1252430243143 its reverse (3413420342521), we get a palindrome (4665850585664).
The spelling of 1252430243143 in words is "one trillion, two hundred fifty-two billion, four hundred thirty million, two hundred forty-three thousand, one hundred forty-three".
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