125244120943 has 4 divisors (see below), whose sum is σ = 125448434968. Its totient is φ = 125039806920.

The previous prime is 125244120931. The next prime is 125244120959. The reversal of 125244120943 is 349021442521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 125244120943 - 2³³ = 116654186351 is a prime.

It is a super-2 number, since 2×125244120943² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125244190943) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102156093 + ... + 102157318.

It is an arithmetic number, because the mean of its divisors is an integer number (31362108742).

Almost surely, 2^125244120943 is an apocalyptic number.

125244120943 is a deficient number, since it is larger than the sum of its proper divisors (204314025).

125244120943 is an equidigital number, since it uses as much as digits as its factorization.

125244120943 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204314024.

The product of its (nonzero) digits is 69120, while the sum is 37.

The spelling of 125244120943 in words is "one hundred twenty-five billion, two hundred forty-four million, one hundred twenty thousand, nine hundred forty-three".