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1252442533 is a prime number
BaseRepresentation
bin100101010100110…
…1100000110100101
310020021200200011111
41022221230012211
510031111130113
6324140105021
743015404646
oct11251540645
93207620144
101252442533
11592a75681
122ab535171
1316c626574
14bc4a16cd
1574e4913d
hex4aa6c1a5

1252442533 has 2 divisors, whose sum is σ = 1252442534. Its totient is φ = 1252442532.

The previous prime is 1252442509. The next prime is 1252442573. The reversal of 1252442533 is 3352442521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1017801409 + 234641124 = 31903^2 + 15318^2 .

It is an emirp because it is prime and its reverse (3352442521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1252442533 - 221 = 1250345381 is a prime.

It is a super-2 number, since 2×12524425332 = 3137224596934912178, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1252442495 and 1252442504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1252442573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626221266 + 626221267.

It is an arithmetic number, because the mean of its divisors is an integer number (626221267).

Almost surely, 21252442533 is an apocalyptic number.

It is an amenable number.

1252442533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252442533 is an equidigital number, since it uses as much as digits as its factorization.

1252442533 is an evil number, because the sum of its binary digits is even.

The product of its digits is 28800, while the sum is 31.

The square root of 1252442533 is about 35389.8648344409. The cubic root of 1252442533 is about 1077.9185255492.

The spelling of 1252442533 in words is "one billion, two hundred fifty-two million, four hundred forty-two thousand, five hundred thirty-three".