Base | Representation |
---|---|
bin | 1011011001000011010011… |
… | …1011011110000111110111 |
3 | 1122100101020122222121000012 |
4 | 2312100310323132013313 |
5 | 3120202211213441442 |
6 | 42345524505010435 |
7 | 2431621326560312 |
oct | 266206473360767 |
9 | 48311218877005 |
10 | 12525012640247 |
11 | 3a99912122108 |
12 | 14a3521483a1b |
13 | 6cb14687b3b3 |
14 | 3142dcb19979 |
15 | 16ac0e8c1582 |
hex | b6434ede1f7 |
12525012640247 has 2 divisors, whose sum is σ = 12525012640248. Its totient is φ = 12525012640246.
The previous prime is 12525012640223. The next prime is 12525012640277. The reversal of 12525012640247 is 74204621052521.
It is a weak prime.
It is an emirp because it is prime and its reverse (74204621052521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12525012640247 - 28 = 12525012639991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12525012640207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6262506320123 + 6262506320124.
It is an arithmetic number, because the mean of its divisors is an integer number (6262506320124).
Almost surely, 212525012640247 is an apocalyptic number.
12525012640247 is a deficient number, since it is larger than the sum of its proper divisors (1).
12525012640247 is an equidigital number, since it uses as much as digits as its factorization.
12525012640247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 268800, while the sum is 41.
Adding to 12525012640247 its reverse (74204621052521), we get a palindrome (86729633692768).
The spelling of 12525012640247 in words is "twelve trillion, five hundred twenty-five billion, twelve million, six hundred forty thousand, two hundred forty-seven".
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