Base | Representation |
---|---|
bin | 10111010101000111… |
… | …11101100000100101 |
3 | 1012022220102121121202 |
4 | 23222203331200211 |
5 | 201122424330432 |
6 | 5430511052245 |
7 | 622246461611 |
oct | 135243754045 |
9 | 35286377552 |
10 | 12525230117 |
11 | 5348190854 |
12 | 2516811085 |
13 | 1247c1178a |
14 | 86b6a0341 |
15 | 4d491e462 |
hex | 2ea8fd825 |
12525230117 has 2 divisors, whose sum is σ = 12525230118. Its totient is φ = 12525230116.
The previous prime is 12525230099. The next prime is 12525230149. The reversal of 12525230117 is 71103252521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8746177441 + 3779052676 = 93521^2 + 61474^2 .
It is a cyclic number.
It is not a de Polignac number, because 12525230117 - 228 = 12256794661 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12525230117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12525230197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6262615058 + 6262615059.
It is an arithmetic number, because the mean of its divisors is an integer number (6262615059).
Almost surely, 212525230117 is an apocalyptic number.
It is an amenable number.
12525230117 is a deficient number, since it is larger than the sum of its proper divisors (1).
12525230117 is an equidigital number, since it uses as much as digits as its factorization.
12525230117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 29.
Adding to 12525230117 its reverse (71103252521), we get a palindrome (83628482638).
The spelling of 12525230117 in words is "twelve billion, five hundred twenty-five million, two hundred thirty thousand, one hundred seventeen".
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