Base | Representation |
---|---|
bin | 111010010100111010… |
… | …1111101100010011101 |
3 | 102222022022101021122101 |
4 | 1310221311331202131 |
5 | 4023011023010013 |
6 | 133313012045101 |
7 | 12022650653425 |
oct | 1645165754235 |
9 | 388268337571 |
10 | 125256063133 |
11 | 49136867153 |
12 | 20338003791 |
13 | ba720cc2b6 |
14 | 60c3421485 |
15 | 33d163c8dd |
hex | 1d29d7d89d |
125256063133 has 2 divisors, whose sum is σ = 125256063134. Its totient is φ = 125256063132.
The previous prime is 125256063103. The next prime is 125256063137. The reversal of 125256063133 is 331360652521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 83127269124 + 42128794009 = 288318^2 + 205253^2 .
It is a cyclic number.
It is not a de Polignac number, because 125256063133 - 29 = 125256062621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 125256063092 and 125256063101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125256063137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62628031566 + 62628031567.
It is an arithmetic number, because the mean of its divisors is an integer number (62628031567).
Almost surely, 2125256063133 is an apocalyptic number.
It is an amenable number.
125256063133 is a deficient number, since it is larger than the sum of its proper divisors (1).
125256063133 is an equidigital number, since it uses as much as digits as its factorization.
125256063133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 125256063133 in words is "one hundred twenty-five billion, two hundred fifty-six million, sixty-three thousand, one hundred thirty-three".
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