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12528005093 = 69111812763
BaseRepresentation
bin10111010101011101…
…00010111111100101
31012100002122121011122
423222232202333211
5201124132130333
65431050343325
7622312200122
oct135256427745
935302577148
1012528005093
11534980671a
12251772ab45
131248673886
1486bbc3749
154d4cbb798
hex2eaba2fe5

12528005093 has 4 divisors (see below), whose sum is σ = 12529824768. Its totient is φ = 12526185420.

The previous prime is 12528005023. The next prime is 12528005123. The reversal of 12528005093 is 39050082521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39050082521 = 135912873231.

It is a cyclic number.

It is not a de Polignac number, because 12528005093 - 212 = 12528000997 is a prime.

It is a super-2 number, since 2×125280050932 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12528005023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 899471 + ... + 913292.

It is an arithmetic number, because the mean of its divisors is an integer number (3132456192).

Almost surely, 212528005093 is an apocalyptic number.

It is an amenable number.

12528005093 is a deficient number, since it is larger than the sum of its proper divisors (1819675).

12528005093 is an equidigital number, since it uses as much as digits as its factorization.

12528005093 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1819674.

The product of its (nonzero) digits is 21600, while the sum is 35.

The spelling of 12528005093 in words is "twelve billion, five hundred twenty-eight million, five thousand, ninety-three".

Divisors: 1 6911 1812763 12528005093