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12530105330147 is a prime number
BaseRepresentation
bin1011011001010110010001…
…1110100010100111100011
31122100212101120210001012122
42312111210132202213203
53120243123431031042
642352130111014455
72432161455662606
oct266254436424743
948325346701178
1012530105330147
113aa0a95888439
1214a4502b0a42b
136cb778991382
1431466322833d
1516ae0ba367d2
hexb65647a29e3

12530105330147 has 2 divisors, whose sum is σ = 12530105330148. Its totient is φ = 12530105330146.

The previous prime is 12530105330131. The next prime is 12530105330159. The reversal of 12530105330147 is 74103350103521.

It is a strong prime.

It is an emirp because it is prime and its reverse (74103350103521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12530105330147 - 24 = 12530105330131 is a prime.

It is not a weakly prime, because it can be changed into another prime (12530105330107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6265052665073 + 6265052665074.

It is an arithmetic number, because the mean of its divisors is an integer number (6265052665074).

Almost surely, 212530105330147 is an apocalyptic number.

12530105330147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12530105330147 is an equidigital number, since it uses as much as digits as its factorization.

12530105330147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 37800, while the sum is 35.

Adding to 12530105330147 its reverse (74103350103521), we get a palindrome (86633455433668).

The spelling of 12530105330147 in words is "twelve trillion, five hundred thirty billion, one hundred five million, three hundred thirty thousand, one hundred forty-seven".