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12530512433 = 39841314513
BaseRepresentation
bin10111010101110000…
…00111001000110001
31012100021100222121002
423222320013020301
5201130302344213
65431220211345
7622342412135
oct135270071061
935307328532
1012530512433
1153501694aa
122518539b55
131249040bca
1486c2773c5
154d5114658
hex2eae07231

12530512433 has 4 divisors (see below), whose sum is σ = 12530866788. Its totient is φ = 12530158080.

The previous prime is 12530512411. The next prime is 12530512441. The reversal of 12530512433 is 33421503521.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4123823089 + 8406689344 = 64217^2 + 91688^2 .

It is a cyclic number.

It is not a de Polignac number, because 12530512433 - 218 = 12530250289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12530512396 and 12530512405.

It is not an unprimeable number, because it can be changed into a prime (12530518433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117416 + ... + 197097.

It is an arithmetic number, because the mean of its divisors is an integer number (3132716697).

Almost surely, 212530512433 is an apocalyptic number.

It is an amenable number.

12530512433 is a deficient number, since it is larger than the sum of its proper divisors (354355).

12530512433 is an equidigital number, since it uses as much as digits as its factorization.

12530512433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 354354.

The product of its (nonzero) digits is 10800, while the sum is 29.

The spelling of 12530512433 in words is "twelve billion, five hundred thirty million, five hundred twelve thousand, four hundred thirty-three".

Divisors: 1 39841 314513 12530512433