Base | Representation |
---|---|
bin | 10010001111000011001… |
… | …011110000001101011111 |
3 | 11102210111101202210222111 |
4 | 102033003023300031133 |
5 | 131012332142340221 |
6 | 2355400522454451 |
7 | 156351144166606 |
oct | 22170313601537 |
9 | 4383441683874 |
10 | 1253110121311 |
11 | 443493aa4334 |
12 | 182a40064427 |
13 | 912247b75a9 |
14 | 44917d28a3d |
15 | 228e2627be1 |
hex | 123c32f035f |
1253110121311 has 2 divisors, whose sum is σ = 1253110121312. Its totient is φ = 1253110121310.
The previous prime is 1253110121293. The next prime is 1253110121401. The reversal of 1253110121311 is 1131210113521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1253110121311 - 213 = 1253110113119 is a prime.
It is a super-2 number, since 2×12531101213112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1253110121611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626555060655 + 626555060656.
It is an arithmetic number, because the mean of its divisors is an integer number (626555060656).
Almost surely, 21253110121311 is an apocalyptic number.
1253110121311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1253110121311 is an equidigital number, since it uses as much as digits as its factorization.
1253110121311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180, while the sum is 22.
Adding to 1253110121311 its reverse (1131210113521), we get a palindrome (2384320234832).
The spelling of 1253110121311 in words is "one trillion, two hundred fifty-three billion, one hundred ten million, one hundred twenty-one thousand, three hundred eleven".
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