Base | Representation |
---|---|
bin | 111010010110100111… |
… | …1010110101001010001 |
3 | 102222110021121120121011 |
4 | 1310231033112221101 |
5 | 4023120120114332 |
6 | 133322405330521 |
7 | 12024242234434 |
oct | 1645517265121 |
9 | 388407546534 |
10 | 125313051217 |
11 | 49165a50142 |
12 | 20353106a41 |
13 | ba80b63363 |
14 | 60cac1781b |
15 | 33d6647e47 |
hex | 1d2d3d6a51 |
125313051217 has 2 divisors, whose sum is σ = 125313051218. Its totient is φ = 125313051216.
The previous prime is 125313051211. The next prime is 125313051341. The reversal of 125313051217 is 712150313521.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 87909878016 + 37403173201 = 296496^2 + 193399^2 .
It is a cyclic number.
It is not a de Polignac number, because 125313051217 - 23 = 125313051209 is a prime.
It is not a weakly prime, because it can be changed into another prime (125313051211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62656525608 + 62656525609.
It is an arithmetic number, because the mean of its divisors is an integer number (62656525609).
Almost surely, 2125313051217 is an apocalyptic number.
It is an amenable number.
125313051217 is a deficient number, since it is larger than the sum of its proper divisors (1).
125313051217 is an equidigital number, since it uses as much as digits as its factorization.
125313051217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 31.
Adding to 125313051217 its reverse (712150313521), we get a palindrome (837463364738).
The spelling of 125313051217 in words is "one hundred twenty-five billion, three hundred thirteen million, fifty-one thousand, two hundred seventeen".
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