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1253143101345 = 3583542873423
BaseRepresentation
bin10010001111000101001…
…001100011111110100001
311102210120200211101002020
4102033011021203332201
5131012414113220340
62355404101412053
7156352024416402
oct22170511437641
94383520741066
101253143101345
1144350067a763
12182a4b10a029
139122b593ac5
144491c4719a9
15228e548e9d0
hex123c5263fa1

1253143101345 has 8 divisors (see below), whose sum is σ = 2005028962176. Its totient is φ = 668342987376.

The previous prime is 1253143101289. The next prime is 1253143101347. The reversal of 1253143101345 is 5431013413521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1253143101345 - 223 = 1253134712737 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1253143101347) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41771436697 + ... + 41771436726.

It is an arithmetic number, because the mean of its divisors is an integer number (250628620272).

Almost surely, 21253143101345 is an apocalyptic number.

1253143101345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1253143101345 is a deficient number, since it is larger than the sum of its proper divisors (751885860831).

1253143101345 is an equidigital number, since it uses as much as digits as its factorization.

1253143101345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83542873431.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 1253143101345 its reverse (5431013413521), we get a palindrome (6684156514866).

The spelling of 1253143101345 in words is "one trillion, two hundred fifty-three billion, one hundred forty-three million, one hundred one thousand, three hundred forty-five".

Divisors: 1 3 5 15 83542873423 250628620269 417714367115 1253143101345