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1253174805097 is a prime number
BaseRepresentation
bin10010001111000111000…
…010100000001001101001
311102210122220111002110021
4102033013002200021221
5131013000222230342
62355411153120441
7156352561042225
oct22170702401151
94383586432407
101253174805097
11443517564206
12182a59859121
1391235014417
1444922765785
15228e8153567
hex123c70a0269

1253174805097 has 2 divisors, whose sum is σ = 1253174805098. Its totient is φ = 1253174805096.

The previous prime is 1253174805073. The next prime is 1253174805121. The reversal of 1253174805097 is 7905084713521.

It is a balanced prime because it is at equal distance from previous prime (1253174805073) and next prime (1253174805121).

It can be written as a sum of positive squares in only one way, i.e., 1251498639616 + 1676165481 = 1118704^2 + 40941^2 .

It is an emirp because it is prime and its reverse (7905084713521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1253174805097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1253174805497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626587402548 + 626587402549.

It is an arithmetic number, because the mean of its divisors is an integer number (626587402549).

Almost surely, 21253174805097 is an apocalyptic number.

It is an amenable number.

1253174805097 is a deficient number, since it is larger than the sum of its proper divisors (1).

1253174805097 is an equidigital number, since it uses as much as digits as its factorization.

1253174805097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2116800, while the sum is 52.

The spelling of 1253174805097 in words is "one trillion, two hundred fifty-three billion, one hundred seventy-four million, eight hundred five thousand, ninety-seven".