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125319814493 = 1215710308449
BaseRepresentation
bin111010010110110100…
…1001001110101011101
3102222110202100012001212
41310231221021311131
54023123333030433
6133323210314205
712024353563436
oct1645551116535
9388422305055
10125319814493
114916984a525
1220355428965
13ba823908b3
1460cba9848d
1533d7031d48
hex1d2da49d5d

125319814493 has 4 divisors (see below), whose sum is σ = 125330135100. Its totient is φ = 125309493888.

The previous prime is 125319814469. The next prime is 125319814507. The reversal of 125319814493 is 394418913521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6965237764 + 118354576729 = 83458^2 + 344027^2 .

It is a cyclic number.

It is not a de Polignac number, because 125319814493 - 210 = 125319813469 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125319814423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5142068 + ... + 5166381.

It is an arithmetic number, because the mean of its divisors is an integer number (31332533775).

Almost surely, 2125319814493 is an apocalyptic number.

It is an amenable number.

125319814493 is a deficient number, since it is larger than the sum of its proper divisors (10320607).

125319814493 is a wasteful number, since it uses less digits than its factorization.

125319814493 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10320606.

The product of its digits is 933120, while the sum is 50.

The spelling of 125319814493 in words is "one hundred twenty-five billion, three hundred nineteen million, eight hundred fourteen thousand, four hundred ninety-three".

Divisors: 1 12157 10308449 125319814493