Base | Representation |
---|---|
bin | 10111010101111100… |
… | …10100100001100011 |
3 | 1012100101102200101012 |
4 | 23222332110201203 |
5 | 201131211441011 |
6 | 5431315131135 |
7 | 622362301460 |
oct | 135276244143 |
9 | 35311380335 |
10 | 12532140131 |
11 | 5351080405 |
12 | 2518ba3aab |
13 | 1249490a44 |
14 | 86c57c667 |
15 | 4d5336a8b |
hex | 2eaf94863 |
12532140131 has 4 divisors (see below), whose sum is σ = 14322445872. Its totient is φ = 10741834392.
The previous prime is 12532140079. The next prime is 12532140133. The reversal of 12532140131 is 13104123521.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13104123521 = 3767 ⋅3478663.
It is a cyclic number.
It is not a de Polignac number, because 12532140131 - 222 = 12527945827 is a prime.
It is a super-2 number, since 2×125321401312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12532140097 and 12532140106.
It is not an unprimeable number, because it can be changed into a prime (12532140133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 895152860 + ... + 895152873.
It is an arithmetic number, because the mean of its divisors is an integer number (3580611468).
Almost surely, 212532140131 is an apocalyptic number.
12532140131 is a deficient number, since it is larger than the sum of its proper divisors (1790305741).
12532140131 is an equidigital number, since it uses as much as digits as its factorization.
12532140131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1790305740.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 12532140131 its reverse (13104123521), we get a palindrome (25636263652).
The spelling of 12532140131 in words is "twelve billion, five hundred thirty-two million, one hundred forty thousand, one hundred thirty-one".
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