Base | Representation |
---|---|
bin | 1011011001100001100010… |
… | …0011001011101111011010 |
3 | 1122101011012010112122002221 |
4 | 2312120120203023233122 |
5 | 3120320320332233132 |
6 | 42353345552014254 |
7 | 2432326362022636 |
oct | 266303043135732 |
9 | 48334163478087 |
10 | 12533126446042 |
11 | 3aa22a6160534 |
12 | 14a500683138a |
13 | 6cbb3a859c07 |
14 | 31486c569dc6 |
15 | 16b036d9be97 |
hex | b66188cbbda |
12533126446042 has 4 divisors (see below), whose sum is σ = 18799689669066. Its totient is φ = 6266563223020.
The previous prime is 12533126446031. The next prime is 12533126446051. The reversal of 12533126446042 is 24064462133521.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12528548705761 + 4577740281 = 3539569^2 + 67659^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 12533126446042.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3133281611509 + ... + 3133281611512.
Almost surely, 212533126446042 is an apocalyptic number.
12533126446042 is a deficient number, since it is larger than the sum of its proper divisors (6266563223024).
12533126446042 is an equidigital number, since it uses as much as digits as its factorization.
12533126446042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6266563223023.
The product of its (nonzero) digits is 829440, while the sum is 43.
Adding to 12533126446042 its reverse (24064462133521), we get a palindrome (36597588579563).
The spelling of 12533126446042 in words is "twelve trillion, five hundred thirty-three billion, one hundred twenty-six million, four hundred forty-six thousand, forty-two".
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