Base | Representation |
---|---|
bin | 111010010111010010… |
… | …1001100000011101011 |
3 | 102222111211221202012012 |
4 | 1310232211030003223 |
5 | 4023141400132420 |
6 | 133324531510135 |
7 | 12024634421165 |
oct | 1645645140353 |
9 | 388454852165 |
10 | 125335552235 |
11 | 49177719523 |
12 | 2035a75834b |
13 | ba85710c7a |
14 | 60cdbd3935 |
15 | 33d85dedc5 |
hex | 1d2e94c0eb |
125335552235 has 4 divisors (see below), whose sum is σ = 150402662688. Its totient is φ = 100268441784.
The previous prime is 125335552213. The next prime is 125335552241. The reversal of 125335552235 is 532255533521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 125335552235 - 216 = 125335486699 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 125335552192 and 125335552201.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12533555219 + ... + 12533555228.
It is an arithmetic number, because the mean of its divisors is an integer number (37600665672).
Almost surely, 2125335552235 is an apocalyptic number.
125335552235 is a deficient number, since it is larger than the sum of its proper divisors (25067110453).
125335552235 is an equidigital number, since it uses as much as digits as its factorization.
125335552235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25067110452.
The product of its digits is 675000, while the sum is 41.
The spelling of 125335552235 in words is "one hundred twenty-five billion, three hundred thirty-five million, five hundred fifty-two thousand, two hundred thirty-five".
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