Base | Representation |
---|---|
bin | 10111010110000111… |
… | …01110000011101011 |
3 | 1012100111002120210212 |
4 | 23223003232003223 |
5 | 201132042233220 |
6 | 5431405331335 |
7 | 622410314642 |
oct | 135303560353 |
9 | 35314076725 |
10 | 12533555435 |
11 | 5351957785 |
12 | 2519566b4b |
13 | 1249867cbb |
14 | 86c82a359 |
15 | 4d55160c5 |
hex | 2eb0ee0eb |
12533555435 has 4 divisors (see below), whose sum is σ = 15040266528. Its totient is φ = 10026844344.
The previous prime is 12533555431. The next prime is 12533555459. The reversal of 12533555435 is 53455533521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12533555435 - 22 = 12533555431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12533555392 and 12533555401.
It is not an unprimeable number, because it can be changed into a prime (12533555431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1253355539 + ... + 1253355548.
It is an arithmetic number, because the mean of its divisors is an integer number (3760066632).
Almost surely, 212533555435 is an apocalyptic number.
12533555435 is a deficient number, since it is larger than the sum of its proper divisors (2506711093).
12533555435 is an equidigital number, since it uses as much as digits as its factorization.
12533555435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2506711092.
The product of its digits is 675000, while the sum is 41.
The spelling of 12533555435 in words is "twelve billion, five hundred thirty-three million, five hundred fifty-five thousand, four hundred thirty-five".
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