12533628441491 has 2 divisors, whose sum is σ = 12533628441492. Its totient is φ = 12533628441490.

The previous prime is 12533628441427. The next prime is 12533628441619. The reversal of 12533628441491 is 19414482633521.

It is a weak prime.

It is an emirp because it is prime and its reverse (19414482633521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12533628441491 - 2⁶ = 12533628441427 is a prime.

It is a super-3 number, since 3×12533628441491³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12533628440491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6266814220745 + 6266814220746.

It is an arithmetic number, because the mean of its divisors is an integer number (6266814220746).

Almost surely, 2^{12533628441491} is an apocalyptic number.

12533628441491 is a deficient number, since it is larger than the sum of its proper divisors (1).

12533628441491 is an equidigital number, since it uses as much as digits as its factorization.

12533628441491 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4976640, while the sum is 53.

The spelling of 12533628441491 in words is "twelve trillion, five hundred thirty-three billion, six hundred twenty-eight million, four hundred forty-one thousand, four hundred ninety-one".