12534312440140 has 24 divisors (see below), whose sum is σ = 26327138801040. Its totient is φ = 5012756847168.

The previous prime is 12534312440131. The next prime is 12534312440201. The reversal of 12534312440140 is 4104421343521.

It is a super-2 number, since 2×12534312440140² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12534312440096 and 12534312440105.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60401887 + ... + 60609046.

It is an arithmetic number, because the mean of its divisors is an integer number (1096964116710).

Almost surely, 2^{12534312440140} is an apocalyptic number.

12534312440140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12534312440140 is an abundant number, since it is smaller than the sum of its proper divisors (13792826360900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12534312440140 is a wasteful number, since it uses less digits than its factorization.

12534312440140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121016121 (or 121016119 counting only the distinct ones).

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 12534312440140 its reverse (4104421343521), we get a palindrome (16638733783661).

The spelling of 12534312440140 in words is "twelve trillion, five hundred thirty-four billion, three hundred twelve million, four hundred forty thousand, one hundred forty".