Search a number
-
+
12534550233404 = 225953112500989
BaseRepresentation
bin1011011001100110110101…
…1010100000000100111100
31122101021212100122112012012
42312121231122200010330
53120331224324432104
642354143132430352
72432406561020333
oct266315532400474
948337770575165
1012534550233404
113aa2966917001
1214a53436183b8
136cc006816944
143149656b0d1a
1516b0bbd8ed6e
hexb666d6a013c

12534550233404 has 12 divisors (see below), whose sum is σ = 22307250415800. Its totient is φ = 6161050114608.

The previous prime is 12534550233383. The next prime is 12534550233427. The reversal of 12534550233404 is 40433205543521.

It is a super-2 number, since 2×125345502334042 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26556250259 + ... + 26556250730.

It is an arithmetic number, because the mean of its divisors is an integer number (1858937534650).

Almost surely, 212534550233404 is an apocalyptic number.

It is an amenable number.

12534550233404 is a deficient number, since it is larger than the sum of its proper divisors (9772700182396).

12534550233404 is a wasteful number, since it uses less digits than its factorization.

12534550233404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53112501052 (or 53112501050 counting only the distinct ones).

The product of its (nonzero) digits is 864000, while the sum is 41.

Adding to 12534550233404 its reverse (40433205543521), we get a palindrome (52967755776925).

The spelling of 12534550233404 in words is "twelve trillion, five hundred thirty-four billion, five hundred fifty million, two hundred thirty-three thousand, four hundred four".

Divisors: 1 2 4 59 118 236 53112500989 106225001978 212450003956 3133637558351 6267275116702 12534550233404