Base | Representation |
---|---|
bin | 1011011001100110111000… |
… | …1101101001111010100111 |
3 | 1122101021220021212210202122 |
4 | 2312121232031221322213 |
5 | 3120331241243034142 |
6 | 42354144332100155 |
7 | 2432410113010445 |
oct | 266315615517247 |
9 | 48337807783678 |
10 | 12534563643047 |
11 | 3aa2973445956 |
12 | 14a534800465b |
13 | 6cc009530444 |
14 | 3149673a1b95 |
15 | 16b0bd13d1d2 |
hex | b666e369ea7 |
12534563643047 has 2 divisors, whose sum is σ = 12534563643048. Its totient is φ = 12534563643046.
The previous prime is 12534563643001. The next prime is 12534563643073. The reversal of 12534563643047 is 74034636543521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12534563643047 - 242 = 8136517131943 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12534563643047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12534563642047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267281821523 + 6267281821524.
It is an arithmetic number, because the mean of its divisors is an integer number (6267281821524).
Almost surely, 212534563643047 is an apocalyptic number.
12534563643047 is a deficient number, since it is larger than the sum of its proper divisors (1).
12534563643047 is an equidigital number, since it uses as much as digits as its factorization.
12534563643047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21772800, while the sum is 53.
The spelling of 12534563643047 in words is "twelve trillion, five hundred thirty-four billion, five hundred sixty-three million, six hundred forty-three thousand, forty-seven".
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