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125351202401352 = 233317761265716883
BaseRepresentation
bin11100100000000110011001…
…111001000010110001001000
3121102211110100211011200022000
4130200012121321002301020
5112412223230303320402
61122333314123431000
735255216436124014
oct3440063171026110
9542743324150260
10125351202401352
1136a39167946a44
1212085aa0085460
1354c374c214a35
1422d505dc41544
15e75a1473cc1c
hex720199e42c48

125351202401352 has 256 divisors, whose sum is σ = 369325289491200. Its totient is φ = 39257084067840.

The previous prime is 125351202401339. The next prime is 125351202401413. The reversal of 125351202401352 is 253104202153521.

125351202401352 is a `hidden beast` number, since 1 + 2 + 5 + 3 + 512 + 0 + 2 + 4 + 0 + 135 + 2 = 666.

It is a super-3 number, since 3×1253512024013523 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7424691103 + ... + 7424707985.

It is an arithmetic number, because the mean of its divisors is an integer number (1442676912075).

Almost surely, 2125351202401352 is an apocalyptic number.

125351202401352 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 125351202401352, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (184662644745600).

125351202401352 is an abundant number, since it is smaller than the sum of its proper divisors (243974087089848).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

125351202401352 is a wasteful number, since it uses less digits than its factorization.

125351202401352 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20333 (or 20323 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 36.

Adding to 125351202401352 its reverse (253104202153521), we get a palindrome (378455404554873).

The spelling of 125351202401352 in words is "one hundred twenty-five trillion, three hundred fifty-one billion, two hundred two million, four hundred one thousand, three hundred fifty-two".