Base | Representation |
---|---|
bin | 10111010110010101… |
… | …10110011000010101 |
3 | 1012100121121112201201 |
4 | 23223022312120111 |
5 | 201133032041113 |
6 | 5431513352501 |
7 | 622432231132 |
oct | 135312663025 |
9 | 35317545651 |
10 | 12535424533 |
11 | 5352a13a95 |
12 | 251a108731 |
13 | 124a070988 |
14 | 86cb95589 |
15 | 4d5784cdd |
hex | 2eb2b6615 |
12535424533 has 2 divisors, whose sum is σ = 12535424534. Its totient is φ = 12535424532.
The previous prime is 12535424527. The next prime is 12535424537. The reversal of 12535424533 is 33542453521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12277083204 + 258341329 = 110802^2 + 16073^2 .
It is a cyclic number.
It is not a de Polignac number, because 12535424533 - 217 = 12535293461 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12535424492 and 12535424501.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12535424537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267712266 + 6267712267.
It is an arithmetic number, because the mean of its divisors is an integer number (6267712267).
Almost surely, 212535424533 is an apocalyptic number.
It is an amenable number.
12535424533 is a deficient number, since it is larger than the sum of its proper divisors (1).
12535424533 is an equidigital number, since it uses as much as digits as its factorization.
12535424533 is an evil number, because the sum of its binary digits is even.
The product of its digits is 216000, while the sum is 37.
The spelling of 12535424533 in words is "twelve billion, five hundred thirty-five million, four hundred twenty-four thousand, five hundred thirty-three".
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