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12535433 is a prime number
BaseRepresentation
bin101111110100…
…011010001001
3212120212101022
4233310122021
511202113213
61124402225
7211356311
oct57643211
925525338
1012535433
117092069
124246375
13279b921
141944441
151179308
hexbf4689

12535433 has 2 divisors, whose sum is σ = 12535434. Its totient is φ = 12535432.

The previous prime is 12535423. The next prime is 12535447. The reversal of 12535433 is 33453521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12411529 + 123904 = 3523^2 + 352^2 .

It is a cyclic number.

It is not a de Polignac number, because 12535433 - 214 = 12519049 is a prime.

It is equal to p820871 and since 12535433 and 820871 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (12535423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267716 + 6267717.

It is an arithmetic number, because the mean of its divisors is an integer number (6267717).

Almost surely, 212535433 is an apocalyptic number.

It is an amenable number.

12535433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12535433 is an equidigital number, since it uses as much as digits as its factorization.

12535433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5400, while the sum is 26.

The square root of 12535433 is about 3540.5413427893. The cubic root of 12535433 is about 232.2985220291.

Adding to 12535433 its reverse (33453521), we get a palindrome (45988954).

The spelling of 12535433 in words is "twelve million, five hundred thirty-five thousand, four hundred thirty-three".