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12535489949 is a prime number
BaseRepresentation
bin10111010110010110…
…00110010110011101
31012100121201212110112
423223023012112131
5201133041134244
65431515015405
7622432622633
oct135313062635
935317655415
1012535489949
115352a59154
12251a13a565
13124a094698
1486cbb1353
154d579939e
hex2eb2c659d

12535489949 has 2 divisors, whose sum is σ = 12535489950. Its totient is φ = 12535489948.

The previous prime is 12535489927. The next prime is 12535489957. The reversal of 12535489949 is 94998453521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10344313849 + 2191176100 = 101707^2 + 46810^2 .

It is an emirp because it is prime and its reverse (94998453521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12535489949 is a prime.

It is a super-2 number, since 2×125354899492 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12535489909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267744974 + 6267744975.

It is an arithmetic number, because the mean of its divisors is an integer number (6267744975).

Almost surely, 212535489949 is an apocalyptic number.

It is an amenable number.

12535489949 is a deficient number, since it is larger than the sum of its proper divisors (1).

12535489949 is an equidigital number, since it uses as much as digits as its factorization.

12535489949 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13996800, while the sum is 59.

The spelling of 12535489949 in words is "twelve billion, five hundred thirty-five million, four hundred eighty-nine thousand, nine hundred forty-nine".