Base | Representation |
---|---|
bin | 10111010110100011… |
… | …10111100011010111 |
3 | 1012100202002000110211 |
4 | 23223101313203113 |
5 | 201134014424333 |
6 | 5432021030251 |
7 | 622453663042 |
oct | 135321674327 |
9 | 35322060424 |
10 | 12537264343 |
11 | 5353a6029a |
12 | 251a855387 |
13 | 124a566216 |
14 | 86d113c59 |
15 | 4d59e9ecd |
hex | 2eb4778d7 |
12537264343 has 2 divisors, whose sum is σ = 12537264344. Its totient is φ = 12537264342.
The previous prime is 12537264307. The next prime is 12537264353. The reversal of 12537264343 is 34346273521.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12537264343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12537264296 and 12537264305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12537264353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6268632171 + 6268632172.
It is an arithmetic number, because the mean of its divisors is an integer number (6268632172).
Almost surely, 212537264343 is an apocalyptic number.
12537264343 is a deficient number, since it is larger than the sum of its proper divisors (1).
12537264343 is an equidigital number, since it uses as much as digits as its factorization.
12537264343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 362880, while the sum is 40.
The spelling of 12537264343 in words is "twelve billion, five hundred thirty-seven million, two hundred sixty-four thousand, three hundred forty-three".
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