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1253748131 is a prime number
BaseRepresentation
bin100101010111010…
…1010110110100011
310020101011000002222
41022232222312203
510031424420011
6324224101255
743032453236
oct11256526643
93211130088
101253748131
11593787589
122aba6482b
1316c9928cc
14bc72141d
1575105ddb
hex4abaada3

1253748131 has 2 divisors, whose sum is σ = 1253748132. Its totient is φ = 1253748130.

The previous prime is 1253748109. The next prime is 1253748163. The reversal of 1253748131 is 1318473521.

It is a weak prime.

It is an emirp because it is prime and its reverse (1318473521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1253748131 is a prime.

It is a super-2 number, since 2×12537481312 = 3143768751971986322, which contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1253748091 and 1253748100.

It is not a weakly prime, because it can be changed into another prime (1253744131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626874065 + 626874066.

It is an arithmetic number, because the mean of its divisors is an integer number (626874066).

Almost surely, 21253748131 is an apocalyptic number.

1253748131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1253748131 is an equidigital number, since it uses as much as digits as its factorization.

1253748131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20160, while the sum is 35.

The square root of 1253748131 is about 35408.3059606076. The cubic root of 1253748131 is about 1078.2929511211.

The spelling of 1253748131 in words is "one billion, two hundred fifty-three million, seven hundred forty-eight thousand, one hundred thirty-one".