1253883334861 has 4 divisors (see below), whose sum is σ = 1253899454112. Its totient is φ = 1253867215612.

The previous prime is 1253883334819. The next prime is 1253883334939. The reversal of 1253883334861 is 1684333883521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1253883334861 - 2⁷ = 1253883334733 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1253883314861) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7942375 + ... + 8098708.

It is an arithmetic number, because the mean of its divisors is an integer number (313474863528).

Almost surely, 2^{1253883334861} is an apocalyptic number.

It is an amenable number.

1253883334861 is a deficient number, since it is larger than the sum of its proper divisors (16119251).

1253883334861 is an equidigital number, since it uses as much as digits as its factorization.

1253883334861 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16119250.

The product of its digits is 9953280, while the sum is 55.

The spelling of 1253883334861 in words is "one trillion, two hundred fifty-three billion, eight hundred eighty-three million, three hundred thirty-four thousand, eight hundred sixty-one".