1253966404913 has 2 divisors, whose sum is σ = 1253966404914. Its totient is φ = 1253966404912.

The previous prime is 1253966404907. The next prime is 1253966404919. The reversal of 1253966404913 is 3194046693521.

It is a balanced prime because it is at equal distance from previous prime (1253966404907) and next prime (1253966404919).

It can be written as a sum of positive squares in only one way, i.e., 1199587896049 + 54378508864 = 1095257^2 + 233192^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1253966404913 is a prime.

It is not a weakly prime, because it can be changed into another prime (1253966404919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626983202456 + 626983202457.

It is an arithmetic number, because the mean of its divisors is an integer number (626983202457).

Almost surely, 2^{1253966404913} is an apocalyptic number.

It is an amenable number.

1253966404913 is a deficient number, since it is larger than the sum of its proper divisors (1).

1253966404913 is an equidigital number, since it uses as much as digits as its factorization.

1253966404913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4199040, while the sum is 53.

The spelling of 1253966404913 in words is "one trillion, two hundred fifty-three billion, nine hundred sixty-six million, four hundred four thousand, nine hundred thirteen".