12539970545 has 4 divisors (see below), whose sum is σ = 15047964660. Its totient is φ = 10031976432.

The previous prime is 12539970539. The next prime is 12539970563. The reversal of 12539970545 is 54507993521.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54507993521 = 47 ⋅1159744543.

It can be written as a sum of positive squares in 2 ways, for example, as 3528835216 + 9011135329 = 59404^2 + 94927^2 .

It is a cyclic number.

It is not a de Polignac number, because 12539970545 - 2⁴ = 12539970529 is a prime.

It is a super-2 number, since 2×12539970545² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12539970493 and 12539970502.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1253997050 + ... + 1253997059.

It is an arithmetic number, because the mean of its divisors is an integer number (3761991165).

Almost surely, 2^12539970545 is an apocalyptic number.

It is an amenable number.

12539970545 is a deficient number, since it is larger than the sum of its proper divisors (2507994115).

12539970545 is an equidigital number, since it uses as much as digits as its factorization.

12539970545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2507994114.

The product of its (nonzero) digits is 1701000, while the sum is 50.

The spelling of 12539970545 in words is "twelve billion, five hundred thirty-nine million, nine hundred seventy thousand, five hundred forty-five".