Base | Representation |
---|---|
bin | 11100100000110100101100… |
… | …011100100001010110100111 |
3 | 121110000012122201220201120022 |
4 | 130200310230130201112213 |
5 | 112414032023342043323 |
6 | 1122412214132225355 |
7 | 35261626230146615 |
oct | 3440645434412647 |
9 | 543005581821508 |
10 | 125400905815463 |
11 | 36a58253157693 |
12 | 1209365176b25b |
13 | 54c83406b0945 |
14 | 22d761700a6b5 |
15 | e76e7304a4c8 |
hex | 720d2c7215a7 |
125400905815463 has 2 divisors, whose sum is σ = 125400905815464. Its totient is φ = 125400905815462.
The previous prime is 125400905815459. The next prime is 125400905815499. The reversal of 125400905815463 is 364518509004521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125400905815463 - 22 = 125400905815459 is a prime.
It is a super-3 number, since 3×1254009058154633 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125400901815463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62700452907731 + 62700452907732.
It is an arithmetic number, because the mean of its divisors is an integer number (62700452907732).
Almost surely, 2125400905815463 is an apocalyptic number.
125400905815463 is a deficient number, since it is larger than the sum of its proper divisors (1).
125400905815463 is an equidigital number, since it uses as much as digits as its factorization.
125400905815463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184000, while the sum is 53.
The spelling of 125400905815463 in words is "one hundred twenty-five trillion, four hundred billion, nine hundred five million, eight hundred fifteen thousand, four hundred sixty-three".
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