125401427 has 2 divisors, whose sum is σ = 125401428. Its totient is φ = 125401426.

The previous prime is 125401403. The next prime is 125401447. The reversal of 125401427 is 724104521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 125401427 - 2¹⁰ = 125400403 is a prime.

It is a Chen prime.

It is equal to p_7131707 and since 125401427 and 7131707 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 125401396 and 125401405.

It is not a weakly prime, because it can be changed into another prime (125401447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62700713 + 62700714.

It is an arithmetic number, because the mean of its divisors is an integer number (62700714).

Almost surely, 2^125401427 is an apocalyptic number.

125401427 is a deficient number, since it is larger than the sum of its proper divisors (1).

125401427 is an equidigital number, since it uses as much as digits as its factorization.

125401427 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2240, while the sum is 26.

The square root of 125401427 is about 11198.2778586709. The cubic root of 125401427 is about 500.5346640649.

Adding to 125401427 its reverse (724104521), we get a palindrome (849505948).

The spelling of 125401427 in words is "one hundred twenty-five million, four hundred one thousand, four hundred twenty-seven".