125403602151133 has 4 divisors (see below), whose sum is σ = 125403703847100. Its totient is φ = 125403500455168.

The previous prime is 125403602151131. The next prime is 125403602151173. The reversal of 125403602151133 is 331151206304521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 45304449416164 + 80099152734969 = 6730858^2 + 8949813^2 .

It is a cyclic number.

It is not a de Polignac number, because 125403602151133 - 2¹ = 125403602151131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125403602151092 and 125403602151101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125403602151131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48975310 + ... + 51472207.

It is an arithmetic number, because the mean of its divisors is an integer number (31350925961775).

Almost surely, 2^{125403602151133} is an apocalyptic number.

It is an amenable number.

125403602151133 is a deficient number, since it is larger than the sum of its proper divisors (101695967).

125403602151133 is a wasteful number, since it uses less digits than its factorization.

125403602151133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101695966.

The product of its (nonzero) digits is 64800, while the sum is 37.

Adding to 125403602151133 its reverse (331151206304521), we get a palindrome (456554808455654).

The spelling of 125403602151133 in words is "one hundred twenty-five trillion, four hundred three billion, six hundred two million, one hundred fifty-one thousand, one hundred thirty-three".