Base | Representation |
---|---|
bin | 10111010110111011… |
… | …10110001001110110 |
3 | 1012100221222112202002 |
4 | 23223131312021312 |
5 | 201140320414332 |
6 | 5432212215302 |
7 | 622522451414 |
oct | 135335661166 |
9 | 35327875662 |
10 | 12540404342 |
11 | 5355805434 |
12 | 251b90a532 |
13 | 124b0c54cb |
14 | 86d6d02b4 |
15 | 4d5e1a562 |
hex | 2eb776276 |
12540404342 has 4 divisors (see below), whose sum is σ = 18810606516. Its totient is φ = 6270202170.
The previous prime is 12540404341. The next prime is 12540404407. The reversal of 12540404342 is 24340404521.
12540404342 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24340404521 = 103 ⋅236314607.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12540404341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3135101084 + ... + 3135101087.
It is an arithmetic number, because the mean of its divisors is an integer number (4702651629).
Almost surely, 212540404342 is an apocalyptic number.
12540404342 is a deficient number, since it is larger than the sum of its proper divisors (6270202174).
12540404342 is an equidigital number, since it uses as much as digits as its factorization.
12540404342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6270202173.
The product of its (nonzero) digits is 15360, while the sum is 29.
Adding to 12540404342 its reverse (24340404521), we get a palindrome (36880808863).
The spelling of 12540404342 in words is "twelve billion, five hundred forty million, four hundred four thousand, three hundred forty-two".
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