125404333 has 2 divisors, whose sum is σ = 125404334. Its totient is φ = 125404332.

The previous prime is 125404277. The next prime is 125404337. The reversal of 125404333 is 333404521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82410084 + 42994249 = 9078^2 + 6557^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-125404333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125404298 and 125404307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125404337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62702166 + 62702167.

It is an arithmetic number, because the mean of its divisors is an integer number (62702167).

Almost surely, 2^125404333 is an apocalyptic number.

It is an amenable number.

125404333 is a deficient number, since it is larger than the sum of its proper divisors (1).

125404333 is an equidigital number, since it uses as much as digits as its factorization.

125404333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 125404333 is about 11198.4076100131. The cubic root of 125404333 is about 500.5385304284.

Adding to 125404333 its reverse (333404521), we get a palindrome (458808854).

The spelling of 125404333 in words is "one hundred twenty-five million, four hundred four thousand, three hundred thirty-three".