1254050423041 has 4 divisors (see below), whose sum is σ = 1350515840212. Its totient is φ = 1157585005872.

The previous prime is 1254050423033. The next prime is 1254050423057. The reversal of 1254050423041 is 1403240504521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 131518649025 + 1122531774016 = 362655^2 + 1059496^2 .

It is a cyclic number.

It is not a de Polignac number, because 1254050423041 - 2³ = 1254050423033 is a prime.

It is a super-2 number, since 2×1254050423041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1254050422994 and 1254050423012.

It is not an unprimeable number, because it can be changed into a prime (1254050423071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48232708566 + ... + 48232708591.

It is an arithmetic number, because the mean of its divisors is an integer number (337628960053).

Almost surely, 2^{1254050423041} is an apocalyptic number.

It is an amenable number.

1254050423041 is a deficient number, since it is larger than the sum of its proper divisors (96465417171).

1254050423041 is an equidigital number, since it uses as much as digits as its factorization.

1254050423041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96465417170.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 1254050423041 its reverse (1403240504521), we get a palindrome (2657290927562).

The spelling of 1254050423041 in words is "one trillion, two hundred fifty-four billion, fifty million, four hundred twenty-three thousand, forty-one".