125405044111 has 4 divisors (see below), whose sum is σ = 125467780000. Its totient is φ = 125342308224.

The previous prime is 125405044091. The next prime is 125405044189. The reversal of 125405044111 is 111440504521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 125405044111 - 2²¹ = 125402946959 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 125405044111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125405044411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31364946 + ... + 31368943.

It is an arithmetic number, because the mean of its divisors is an integer number (31366945000).

Almost surely, 2^125405044111 is an apocalyptic number.

125405044111 is a deficient number, since it is larger than the sum of its proper divisors (62735889).

125405044111 is an equidigital number, since it uses as much as digits as its factorization.

125405044111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62735888.

The product of its (nonzero) digits is 3200, while the sum is 28.

Adding to 125405044111 its reverse (111440504521), we get a palindrome (236845548632).

The spelling of 125405044111 in words is "one hundred twenty-five billion, four hundred five million, forty-four thousand, one hundred eleven".