Base | Representation |
---|---|
bin | 111010011001100011… |
… | …0010000000000000011 |
3 | 102222201010112120000010 |
4 | 1310303012100000003 |
5 | 4023320244444003 |
6 | 133340240000003 |
7 | 12026544461613 |
oct | 1646306200003 |
9 | 388633476003 |
10 | 125411328003 |
11 | 49206474a25 |
12 | 20380000003 |
13 | ba983226c0 |
14 | 60d9cbaa43 |
15 | 33e00ac003 |
hex | 1d33190003 |
125411328003 has 16 divisors (see below), whose sum is σ = 180144478976. Its totient is φ = 77147627040.
The previous prime is 125411328001. The next prime is 125411328137. The reversal of 125411328003 is 300823114521.
It is not a de Polignac number, because 125411328003 - 21 = 125411328001 is a prime.
It is a super-3 number, since 3×1254113280033 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (125411328001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 488383 + ... + 699528.
It is an arithmetic number, because the mean of its divisors is an integer number (11259029936).
Almost surely, 2125411328003 is an apocalyptic number.
125411328003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
125411328003 is a deficient number, since it is larger than the sum of its proper divisors (54733150973).
125411328003 is a wasteful number, since it uses less digits than its factorization.
125411328003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1190634.
The product of its (nonzero) digits is 5760, while the sum is 30.
The spelling of 125411328003 in words is "one hundred twenty-five billion, four hundred eleven million, three hundred twenty-eight thousand, three".
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