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1254113423449 is a prime number
BaseRepresentation
bin10010001111111110111…
…111000011000001011001
311102220002022122211202221
4102033332333003001121
5131021411014022244
62400044243024041
7156415046132665
oct22177677030131
94386068584687
101254113423449
11443959373057
1218308006b021
139135460c7b3
14449b12958a5
152295075c784
hex123fefc3059

1254113423449 has 2 divisors, whose sum is σ = 1254113423450. Its totient is φ = 1254113423448.

The previous prime is 1254113423383. The next prime is 1254113423461. The reversal of 1254113423449 is 9443243114521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 723937214025 + 530176209424 = 850845^2 + 728132^2 .

It is a cyclic number.

It is not a de Polignac number, because 1254113423449 - 211 = 1254113421401 is a prime.

It is a super-3 number, since 3×12541134234493 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1254113483449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627056711724 + 627056711725.

It is an arithmetic number, because the mean of its divisors is an integer number (627056711725).

Almost surely, 21254113423449 is an apocalyptic number.

It is an amenable number.

1254113423449 is a deficient number, since it is larger than the sum of its proper divisors (1).

1254113423449 is an equidigital number, since it uses as much as digits as its factorization.

1254113423449 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 414720, while the sum is 43.

The spelling of 1254113423449 in words is "one trillion, two hundred fifty-four billion, one hundred thirteen million, four hundred twenty-three thousand, four hundred forty-nine".